Using Ohm's law, if the voltage doubles while resistance remains constant, what happens to the current?

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Multiple Choice

Using Ohm's law, if the voltage doubles while resistance remains constant, what happens to the current?

Explanation:
Current is directly proportional to voltage when resistance stays constant, according to Ohm's law I = V / R. If the voltage doubles while the resistance remains the same, the current must also double because I becomes (2V)/R = 2(V/R). For example, with 6 V across 3 Ω, I is 2 A; with 12 V across the same 3 Ω, I is 4 A. So doubling the voltage doubles the current. The other options would require different changes in voltage or resistance.

Current is directly proportional to voltage when resistance stays constant, according to Ohm's law I = V / R. If the voltage doubles while the resistance remains the same, the current must also double because I becomes (2V)/R = 2(V/R). For example, with 6 V across 3 Ω, I is 2 A; with 12 V across the same 3 Ω, I is 4 A. So doubling the voltage doubles the current. The other options would require different changes in voltage or resistance.

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